1860 United States presidential election in Missouri
|Elections in Missouri|
The 1860 United States presidential election in Missouri took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.
Missouri was won by Democratic candidate, Stephen A. Douglas. He won the state by a very narrow margin of 0.26%. The state was the only one to fully give its votes to Douglas, though he would win the popular vote and three of the seven electoral votes from New Jersey under a fusion ticket.
As of the 2016 presidential election[update], this is the last occasion when Putnam County voted for a Democratic presidential candidate and the last occasion when Taney County did not vote for the Republican candidate.
|Democratic||Stephen A. Douglas||58,801||35.73%|
|Constitutional Union||John Bell||58,372||35.26%|
|Southern Democratic||John C. Breckinridge||31,362||18.94%|
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