1877 Iowa gubernatorial election

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1877 Iowa gubernatorial election

← 1875 October 9, 1877 1879 →
  John Henry Gear - Senator.jpg John p irish.jpg No image.svg
Nominee John H. Gear John P. Irish Daniel P. Stubbs
Party Republican Democratic Greenback
Popular vote 121,316 79,304 34,316
Percentage 49.39% 32.29% 13.97%

Governor before election

Joshua G. Newbold
Republican

Elected Governor

John H. Gear
Republican

The 1877 Iowa gubernatorial election was held on October 9, 1877. Republican nominee John H. Gear defeated Democratic nominee John P. Irish with 49.39% of the vote.

General election[edit]

Candidates[edit]

Major party candidates

  • John H. Gear, Republican
  • John P. Irish, Democratic

Other candidates

  • Daniel P. Stubbs, Greenback
  • Elias Jessup, Prohibition

Results[edit]

1877 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican John H. Gear 121,316 49.39%
Democratic John P. Irish 79,304 32.29%
Greenback Daniel P. Stubbs 34,316 13.97%
Prohibition Elias Jessup 10,565 4.30%
Majority 42,012
Turnout
Republican hold Swing

References[edit]

  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved September 21, 2020.