1956 Iowa gubernatorial election

From Wikipedia, the free encyclopedia
Jump to navigation Jump to search
1956 Iowa gubernatorial election
Flag of Iowa (variant).svg
← 1954 November 6, 1956 1958 →
  Herschel C. Loveless.jpg Leo Hoegh.png
Nominee Herschel C. Loveless Leo Hoegh
Party Democratic Republican
Popular vote 616,852 587,383
Percentage 51.22% 48.78%

Iowa Governor Election Results by County, 1956.svg
County results
Loveless:      50–60%      60–70%
Hoegh:      50-60%      60-70%

Governor before election

Leo Hoegh
Republican

Elected Governor

Herschel C. Loveless
Democratic

The 1956 Iowa gubernatorial election was held on November 6, 1956. Democratic nominee Herschel C. Loveless defeated incumbent Republican Leo Hoegh with 51.22% of the vote.

Primary elections[edit]

Primary elections were held on June 4, 1956.[1]

Democratic primary[edit]

Candidates[edit]

Results[edit]

Democratic primary results[1]
Party Candidate Votes %
Democratic Herschel C. Loveless 77,206 70.0
Democratic Lawrence E. Plummer 33,103 30.0
Total votes 110,309 100.00

Republican primary[edit]

Candidates[edit]

Results[edit]

Republican primary results[1]
Party Candidate Votes %
Republican Leo Hoegh 188,290 100.00
Total votes 188,290 100.00

General election[edit]

Candidates[edit]

  • Herschel C. Loveless, Democratic
  • Leo Hoegh, Republican

Results[edit]

1956 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Democratic Herschel C. Loveless 616,852 51.22%
Republican Leo Hoegh 587,383 48.78%
Majority 29,469
Turnout 1,204,235
Democratic gain from Republican Swing

References[edit]

  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1956. Retrieved March 28, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1956. Retrieved March 28, 2020.